Q.1 Solution:
55fbd96d-66e7-45e7-b7bd-a16e105c32ce-image.png
Anti clockwise moment = Clockwise moment
8gN * d = 2gN * 2.5m
8d = 5Nm
d = 5/8
d = 0.625m
= 4 – d
= 4 – ( 0.625)
= 3.375m

Q. 2 Solution:
2d8517b3-5885-4944-b418-04e787ef907d-image.png
R = 0
Taking moment about ‘C’
w * 0.5 = 6 * 1N + 5 * 4m
0.5w = 26Nm
w = 26/0.5m
w = 52 N

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Solution of Assignment # 1 MTH304 (Fall 2019)

Maximum Marks: 20
Due Date: 17 -11-2019

Question No. 1:

A particle of mass 10kg is placed on an inclined plane which makes and angle of with the horizontal. Find the resolved parts of the weight of the particle in the direction parallel and perpendicular to the plane. MARKS 10
Solution
3480151d-364b-4d32-8c7d-08ecd937e68c-image.png

Question No. 2:

Two particles of mass 3kg each are connected by a light inextensible string which passes over a smooth fixed pulley, which is attached to a string C. The string C is hanging on the fixed support. The particles are at rest. Find the tension in the string C. MARKS 10

Solution
f2e46de8-2a58-4ad4-a49e-eb3c478212e0-image.png