CS301 – Data Structures

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  SOLVED CS301 Assignment 2 Solution and Discussion Spring 2020
  solution discussion assignment 2 spring 2020 cs301 • • zaasmi  

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  #include<iostream> using namespace std; class TNode{ private: node* root; public: TNode(); int isEmpty(); void buildTree(int item); void insert(int item,node *,node *); void minNode(node*); void maxNode(node*); int countNodes(node*); int treeHeight(node*); void displayBinTree(); }; TNode::TNode(){ root = NULL; } int TNode::isEmpty() { return (root == NULL); } void TNode::buildTree(int item){ node *p = new node; node *parent; cout <<"Insert node in BST :" << item <<endl; insert(item,p,parent); } void TNode::insert(int item,node * p,node * parent){ p->data=item; p->left=NULL; p->right=NULL; parent=NULL; if(isEmpty()){ root = p; } else{ node *ptr; ptr = root; while(ptr != NULL){ parent = ptr; if(item > ptr->data){ ptr = ptr->right; } else{ ptr = ptr->left; } } if(item < parent->data){ parent->left = p; } else{ parent->right = p; } } } void TNode::minNode(node* p){ while (p->left != NULL){ p = p->left; } cout << "Minimum value : " << p->data <<endl; } void TNode::maxNode(node* p){ while (p->right != NULL){ p = p->right; } cout << "Maximum value : " << p->data <<endl; } int TNode::countNodes(node* p){ int node = 1; //Node itself should be counted if (p == NULL){ return 0; } else{ node += countNodes(p->left); node += countNodes(p->right); return node; } } int TNode::treeHeight(node* p){ if (p == NULL) { return 0; } else { int left_side = treeHeight(p->left); int right_side = treeHeight(p->right); if (left_side > right_side) { return(left_side + 1); } else { return(right_side + 1); } } } void TNode::displayBinTree(){ cout <<endl<<endl; minNode(root); maxNode(root); cout <<"Height of BST : "<<treeHeight(root); cout <<"\nTotal nodes : "<<countNodes(root); } int main(){ TNode b; int data[] = {7,2,9,1,5,14}; cout <<"Constructing Binary Search Tree by Inserting Nodes One by One "<<endl; cout <<"------------------------------------------------------------- "<<endl; int arrSize = sizeof(data)/sizeof(data[0]); for(int i = 0; i < arrSize; i++) { b.buildTree(data[i]); } }
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  SOLVED CS301 Assignment 1 Solution and Discussion
  solution discussion assignment 1 spring 2020 cs301 • • zaasmi  

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  /* Implementation of stack using array */ #include <iostream> #include <conio.h> using namespace std; class Stack /* the Stack class */ { public: Stack() { size = 0; current = -1; } //constructor int pop() { return data[current--]; } // The pop function void push(int x) { data[++current] = x; //cout<<A[current]; } // The push function int top(){ return data[current]; } // The top function int isEmpty(){ return ( current == -1 ); } // Will return true when stack is empty int isFull(){ return ( current == size-1); } // Will return true when stack is full void setStackSize(int s){ size = s; data = new int[size]; } private: int object; // The data element int current; // Index of the array int size; // max size of the array int *data; // Array of 10 elements }; // Main method int main() { int t_books= 0, size = 0; int scount = 0, hcount=0, ocount=0; // For counting of book i.e software , hardware and other books. Stack stack; // creating a stack object cout<<"Set size of stack: "; cin>>size; stack.setStackSize(size); cout<<"How many Books you want to add into stack: "; cin>>t_books; int book; for(int i = 0; i < t_books; i++) { cout <<"\nEnter Book identity number that you want to insert into stack: "; cin>>book; if(!stack.isFull()) { // checking stack is full or not stack.push(book); // push the element at the top } else{ cout<<"\n Unable to insert "<<book<<". Stack is full, can't insert more"; break; } } // pop the elements at the stack int current = 0; for (int i = 0; i < t_books; i++) { if(!stack.isEmpty()) { // checking stack is empty or not current = stack.pop(); if(current % 8 == 0){ scount++; } else if(current % 5 == 0){ hcount++; } else { ocount++; } } else { cout <<"\nStack is empty, sorry can't pop more"; getch(); break; } } if(scount == 0 && hcount==0 && ocount==0){ cout<<"\nBooks not found\n"; } else { cout<<"\n\nTotal Software Book/Books = "<<scount; cout<<"\n\nTotal Hardware Book/Books = "<<hcount; cout<<"\n\nTotal Other Book/Books = "<<ocount; } getch(); }
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  CS301 GDB 1 Solution and Discussion
  solution discussion fall 2019 gdb 1 cs301 • • zareen  

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  SOLVED CS301 Assignment 2 Solution and Discussion
  solution discussion fall 2019 assignment 2 cs301 • • zareen  

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  100% Solved: #include <iostream> #include <string.h> using namespace std; const int arrLength = 10; struct Student{ string userVUID; string userDetails; }std1={"NULL","NULL"}; class ArrQueue{ private: //Data Members Student arr[arrLength]; int front; int rear; public: //Constructor ArrQueue(){ for(int i=0; i<arrLength; i++) arr[i] = std1; front = -1; rear = -1; } //Member Functions void enQue(Student std){ if(isEmpty()){ arr[0] = std; front++; rear++; } else if(isFull()){ cout << " Queue is full."; } else{ arr[rear+1] = std; rear++; } } void deQue(){ if(isEmpty()){ cout<< " No Student In the Queue.\n"; } else if(rear == 0){ arr[front] = std1; front = -1; rear = -1; } else{ int tempfront = front; arr[front] = std1; for(int i=1; i<=rear; i++ ){ arr[front] = arr[i]; front++; } rear--; front = tempfront; } } int queLength(){ return rear+1; } bool isEmpty(){ if(front==-1 || rear==-1) return true; else return false; } bool isFull(){ if(rear == arrLength-1) return true; else return false; } void showQue(){ cout << "\n |Sr. VU ID Details |"; cout << "\n --- -------------------------------\n"; for(int i=front; i<=rear; i++){ cout<<" "<< i+1<< ". "<< arr[i].userVUID << " " << arr[i].userDetails <<"\n"; } } }; int main(){ /*Code For Even Id's Student std[] = {{"BC12345684","Bilal (BSCS)"}, {"BC12345685","Bilal (BSCS)"},{"BC12345686","Bilal (BSCS)"},{"BC12345687","Bilal (BSCS)"}, {"BC12345688","Bilal (BSCS)"}};*/ /*Code For Odd Id's */ Student std[] = {{"BC12345683","Bilal (BSCS)"}, {"BC12345684","Bilal (BSCS)"},{"BC12345685","Bilal (BSCS)"},{"BC12345686","Bilal (BSCS)"}, {"BC12345687","Bilal (BSCS)"}}; ArrQueue arrQue; cout << "\n -----------------------------------"; cout << "\n | Queue (After Adding Students) |"; cout << "\n -----------------------------------"; for(int i=0; i<=4; i++){ arrQue.enQue(std[i]); } arrQue.showQue(); cout << "\n -----------------------------------"; cout << "\n | Queue (After Removing Students) |"; cout << "\n -----------------------------------"; /* Code For Even Id's for(int i=0; i<=1; i++){ arrQue.deQue(); }*/ /*Code For Odd Id's*/ for(int i=0; i<1; i++){ arrQue.deQue(); } arrQue.showQue(); }
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  UNSOLVED CS301 Assignment 3 Solution and Discussion
  solution discussion fall 2019 assignment 3 cs301 • • zareen  

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  Solution Idea! #include <bits/stdc++.h> using namespace std; class HeapNode_Min { // Tree node of Huffman public: //Add data members here. char d; unsigned f; HeapNode_Min *l, *r; HeapNode_Min(char d, unsigned f = -1) { //Complete the body of HeapNode_Min function this->d = d; this->f = f ; this->l = NULL; this->r = NULL; } }; class Analyze { // two heap nodes comparison public: bool operator()(HeapNode_Min* l, HeapNode_Min* r) { //add return before statement and statement is completed. return (l->f > r->f); //Complete this statement } }; void display_Codes(HeapNode_Min* root, string s) // To print codes of huffman tree from the root. { if (!root) return; if (root->d != '$') cout root->d "\t: " s "\n"; display_Codes(root->l, s + "0"); display_Codes(root->r, s + "1"); //Complete this statement by passing arguments } void HCodes(char data[], int freq[], int s) // builds a Huffman Tree { HeapNode_Min *t,*r, *l ; // top, right, left priority_queue<HeapNode_Min*, vector<HeapNode_Min*>, Analyze> H_min; int a=0; while (a<s){H_min.push(new HeapNode_Min(data[a], freq[a])); ++a;} while (H_min.size() != 1) { l = H_min.top(); H_min.pop(); r = H_min.top(); H_min.pop(); t = new HeapNode_Min('$', r->f + l->f); t->r = r; t->l = l; H_min.push(t); } display_Codes(H_min.top(), ""); } int main() { int frequency[] = { 3, 6, 11, 14, 18, 25 }; char alphabet[] = { 'A', 'L', 'O', 'R', 'T', 'Y' }; //Complete this statement by passing data type to both sizeof operators int size_of = sizeof(alphabet) / sizeof(*alphabet); cout"Alphabet"":""Huffman Code\n"; cout"--------------------------------\n"; //Call Huffman_Codes function. HCodes(alphabet, frequency, size_of); return 0; }
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  CS301 Quiz 1 Solution and Discussion
  solution discussion fall 2019 quiz 1 cs301 • • zareen  

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  SOLVED CS301 Assignment 1 Solution and Discussion
  solution discussion fall 2019 assignment 1 cs301 • • zareen  

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  .CPP File Code using namespace std; #include <stdlib.h> #include <iostream> struct StudentDetail{ string name; string vuid; }; //class Node* head; class Node{ struct StudentDetail newStd; class Node* next; class Node* prev; void Set(string name,string vuid) { newStd.name=name; newStd.vuid=vuid; } Node Get() { } void setNext(string name,string vuid){ if(next==NULL) { } else { class Node* newNode= new Node(); newStd.name=name; newStd.vuid=vuid; newNode->next= newNode; } } string getNext() { next; } void setPrev(string name,string vuid){ if(next==NULL) { } else { class Node* newNode= new Node(); newStd.name=name; newStd.vuid=vuid; newNode->next= newNode; } } string getPrev() { prev; } }; class DoublyLinkedList{ public: struct StudentDetail newStd; class DoublyLinkedList* headPtr; class DoublyLinkedList* curPtr; class DoublyLinkedList* nextPtr; int size; //dfdf class DoublyLinkedList* headDlinkList=NULL; void addAtBegining(string vuid, string name) { class DoublyLinkedList* dNode= new DoublyLinkedList(); dNode->newStd.vuid=vuid; dNode->newStd.name=name; dNode->nextPtr=headDlinkList; headDlinkList= dNode; dNode->curPtr=dNode; } void addAtEnd(string vuid, string name) { class DoublyLinkedList* dNode= new DoublyLinkedList(); dNode->newStd.vuid=vuid; dNode->newStd.name=name; dNode->nextPtr=headDlinkList; headDlinkList= dNode; dNode->curPtr=dNode; } void delNode() { class DoublyLinkedList* temp1=curPtr; class DoublyLinkedList* temp2= temp1; temp1->nextPtr= temp2->nextPtr; free(temp2); } void print() { class DoublyLinkedList* temp= headDlinkList; while(temp!=NULL) { cout<<temp->newStd.vuid<<" "<<temp->newStd.name<<endl; temp= temp->nextPtr; } } }; int main() { string vuid,name; cout<<"Add your vuID and Name at First Position "<<endl; cout<<"_ _ _ _ _ _ _ _ __ _ _ _ _ _ _ _ __ _ _ _ _ _ _ _ __ _ _"<<endl; DoublyLinkedList dlist1; cin>>vuid; cin>>name; dlist1.addAtBegining(vuid,name); dlist1.print(); cout<<"Insertion At Beginning in doubly Link List "<<endl; cout<<"_ _ _ _ _ _ _ _ __ _ _ _ _ _ _ _ __ _ _ _ _ _ _ _ __ _ _"<<endl; cin>>vuid; cin>>name; dlist1.addAtBegining(vuid,name); dlist1.print(); cout<<"Insertion At End in doubly Link List "<<endl; cout<<"_ _ _ _ _ _ _ _ __ _ _ _ _ _ _ _ __ _ _ _ _ _ _ _ __ _ _"<<endl; cin>>vuid; cin>>name; dlist1.addAtEnd(vuid,name); dlist1.print(); cout<<"Deletion of Current Node (Last Node) "<<endl; cout<<"_ _ _ _ _ _ _ _ __ _ _ _ _ _ _ _ __ _ _ _ _ _ _ _ __ _ _"<<endl; dlist1.delNode(); dlist1.print(); } Download .cpp File
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  UNSOLVED CS301 Final Term Current Paper
  spring 2019 final term current paper phy101 • • zareen  

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  @zareen The Linked List ADT We have been using linked nodes to generate our structures for the Stack ADT and the Queue ADT. Now we will consider the linked list. As we have been using this structure for implementing the previous ADT structures, it is perhaps more constructive to look at a variation of the single linked list (known as the ‘sorted’ linked list). The idea behind this type of list is that any element we put into the list will have to be put into the correct position by comparing some common value held in each of the nodes. So far the Stack ADT and the Queue ADT did not impose any ordering on the elements we added. If we were looking for a basic linked list, we could use these as the basis for the structure and operations. This is a task you might attempt for yourselves. Our sorted linked list ADT will consist of the following primitive operations: Create() Destroy() Add(element) Remove(element) Traverse() IsEmpty() Search(element) We would generally need a display operation for testing purposes to ensure that the elements are being put into the correct locations. However, the Sorted linked list is a linear structure so any processing done on the list has to be carried out in a linear manner. We must access the list through the Start link / pointer and the list has to be accessed/processed in the order that the nodes appear on the list. As we have previously seen, one of the great advantages of the linked data structure is the ease with which it may be modified. Changing the structure does not involve moving the existing nodes. In order to delete a node we update the link / pointer of the node before it and point / link this to the node after it. Source