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MKT731 Assignment 1 Solution and Discussion

MKT731 - Consumer Behaviour

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Provide a brief summary of the article titled “Popularity of Brand Posts on Brand Fan Pages: An Investigation of the effects of Social Media Marketing”
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SOLVED CS406 Assignment 1 Solution and Discussion
CS406 - Web Based Database Applications • cs406 assignment 1 solution discussion spring 2020 • • moaaz

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<html> <title></title> <body> <h1><U>Student Profile Form</U></h1></div> <form action="form.php" method="POST"> <table> <tr> <td width="50%">Student ID </td> <td width="50%"><INPUT TYPE = "text" NAME="sID"></td> </tr> <tr> <td width="50%">Form No </td> <td width="50%"><INPUT TYPE = "Number" NAME="fNO"></td> </tr> <tr> <td width="50%">Name</td> <td width="50%"><INPUT TYPE = "text" NAME="sName" ></td> </tr> <tr> <td width="50%">Current Semester</td> <td width="50%"><INPUT TYPE = "text" NAME="cSem"></td> </tr> <tr> <td width="50%">CGPA</td> <td width="50%"> <INPUT TYPE = "Number" NAME="sCGPA"></td> </tr> <tr> <td width="50%">Entery Test Qualified</td> <td width="50%"><input type="radio" name="ETQ"> Yes <input type="radio" name="ETQ"> No</td> </tr> <tr> <td width="50%">Study Program</td> <td width="50%"><select name="SP" id="SP"> <option value="bs">Please Select</option> <option value="bs">BSCS</option> <option value="mc">MCS</option> <option value="ms">MSCS</option> </select> </td> </tr> <tr> <td width="50%">VU Email</td> <td width="50%"><INPUT TYPE = "Text" NAME="emAddress"></td> </tr> <tr> <td width="50%">Mobile No</td> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> </tr> <tr> <td width="50%">Address</td> <td width="50%"><INPUT TYPE = "Text" NAME="sAddress"></td> </tr> <table> <thead> <tr> <th rowspan="5">Academic Qualifications</th> <th>Certificate/Degree Name</th> <th>Name of Institute</th> <th>Registration Number</th> <th>Obtained Marks/CGPA</th> <th>Total Marks/CGPA</th> </tr> <tr> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> </tr> <tr> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> </tr> <tr> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> </tr> <tr> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> <td width="50%"> <INPUT TYPE = "Number" NAME="sMob"></td> </tr> </thead> </table> <tr> <table> <tr> <td align="center"></td> <td style="text-align:center" width="50%"><INPUT TYPE = "submit" NAME="Submit"></td> <td align="center"></td> <td style="text-align:center" width="50%"><INPUT TYPE = "reset" NAME="Reset"></td> </tr> </table> </form> </body> </html>
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Guidelines for solution:
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ZOO501 - Developmental Biology • zoo501 assignment 1 solution discussion fall 2019 • • zareen

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@zareen said in ZOO501 Assignment 2 Solution and Discussion:

Differentiate between uterine endometrium and chorion (05)

The endometrium is the inner epithelial layer, along with its mucous membrane, of the … Vascular spaces fuse and become interconnected, forming the placenta, … These two layers occur only in the endometrium lining the cavity of the uterus, … the ovarian cycle or the uterine cycle by observing microscopic differences at …

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MGT604 - Management of Financial Institutions (alt. code=BNK604) • mgt604 gdb 1 solution discussion fall 2019 • • zareen

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SOLVED PHY301 Assignment 1 Solution and Discussion
PHY301 - Circuit Theory • phy301 assignment 1 solution discussion fall 2019 • • zareen

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Q. 1 Solution:
Starting from lower side of circuit network, we can see that 2Ω and 2Ω are in series, so their combined effect is
2+2=4Ω
97b5d636-b0d8-40d1-8f33-9266b3779585-image.png

This 4Ω is in parallel of 4Ω to lower side, so their equivalent is

1b08526d-0c95-43b2-9f73-3927652469d8-image.png

0888b8c5-aeba-4acd-9184-9f1a8f70b1ef-image.png

This 2Ω is in series of 5Ω and 1Ω, so the sum of series resistances is

2Ω+ 5Ω+1Ω=8Ω
f1ffb19b-69a3-4eb0-8d8d-4eb1316289f4-image.png

Now at upper side, 4Ω and 2Ω are in series
4Ω+ 2Ω=6Ω
b3a9072f-b02e-4881-aaf3-9b389aab13e0-image.png

This 6Ω is in parallel of 6Ω, so their equivalent is
df9ccb62-3a78-4fec-a9d8-9044a372be75-image.png

cac80a33-5165-4e48-b124-810aaad24d2e-image.png

This 3Ω is in series of 3Ω and 1Ω, so the sum of series is

3Ω+ 3Ω+1Ω=7Ω
051e272e-1e7b-48b8-9359-4810dcb187d5-image.png

Now we can see 7Ω becomes in series of 8Ω, so equivalent resistance is
Req =7Ω + 8Ω
Req=15Ω

Q.2 Solution:
1)
To calculate the source current Is, Firstly, we calculate the total resistance
RT= R1+R2+R3
=6Ω
V=IR
IS=VS/RT
= 12/6
=2A

2)
Since all resistances are in series, same 2A current pass through each resistance.
V1= R1IS
=12
=2V
V2=R2Is
=22
=4V
V3=R3IS
= 32
=6V

3)
P1 =I2R1
= (2)2 *1
=4W
P2 =I2R2
= (2)2 *2
= 8W
P3 =I2R3
=(2)2 *3
= 12W
= 12W

4)-
Ps = VsIs
P =122
=24 W
PT=P1+P2+P3 or PT=I2RT
=4+8+12
=24 W

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MKT731 Assignment 1 Solution and Discussion

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100% Off on Your FEE Join US! Ask Me How?

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CS406 - Web Based Database Applications • cs406 assignment 1 solution discussion spring 2020 • • moaaz

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BIO102 - Basic II-Chemistry • bio102 gdb 1 solution discussion fall 2019 • • zareen

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UNSOLVED MGT604 GDB 1 Solution and Discussion
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