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  If the equation \(y=\dfrac{1}{6} (x+12)\) were graphed in the \(xy-plane\), which of the following statements would be true of the graphed line?

  It would be perpendicular to the graph of \(y=\dfrac{1}{6}x+3\).

  It would be parallel to the graph of \(12y=2x+3\).

  It would have the same slope as the graph of \(x+6y=18\).

  It would have the same \(y\)‑intercept as the graph of \(y=\dfrac{1}{6}x+12\).

  I would be guessing.