Skip to content

Competition Exam Preparation and Discussions

7 Topics 10 Posts

Subcategories


  • CSS Exam Preparation and Discussion Form
    0 Topics
    0 Posts
    No new posts.
  • PMS Exam Preparation and Discussion Forum
    0 Topics
    0 Posts
    No new posts.
  • PCS Exam Preparation and Discussion forum
    0 Topics
    0 Posts
    No new posts.
  • PPSC Exam Preparation and Discussion forum
    0 Topics
    0 Posts
    No new posts.
  • FPSC Exam Preparation and Discussion forum
    0 Topics
    0 Posts
    No new posts.
  • 1 Topics
    2 Posts
    zareenZ

    If the equation \(y=\dfrac{1}{6} (x+12)\) were graphed in the \(xy-plane\), which of the following statements would be true of the graphed line?

    It would be perpendicular to the graph of \(y=\dfrac{1}{6}x+3\).

    It would be parallel to the graph of \(12y=2x+3\).

    It would have the same slope as the graph of \(x+6y=18\).

    It would have the same \(y\)‑intercept as the graph of \(y=\dfrac{1}{6}x+12\).

    I would be guessing.