CS601 Assignment 2 Solution and Discussion


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    Assignment No. 02
    Semester: Fall 2019
    CS601: Data Communication Total Marks: 20

    Due Date: 28 Nov 2019

    Instructions:
    Please read the following instructions carefully before submitting assignment:
    You need to use MS word document to prepare and submit the assignment on VU-LMS.
    It should be clear that your assignment will not get any credit if:

     The assignment is submitted after due date.
     The assignment is not in the required format (doc or docx).
     The submitted assignment does not open or file is corrupt.
     Assignment is copied (partial or full) from any source (websites, forums, students, etc).

    Objectives:

    To enhance the learning about:

    1. Encoding Scheme
    2. Single Characteristics
    3. Transmission Impairments

    Assignment

    Question No. 1

    A below given diagram is representing the Differential Manchester encoding scheme. You are required to carefully analyze the diagram and then write the binary pattern represented by the diagram:
    a1816ce8-091c-4f41-aa0c-d1984eed8ae6-image.png

    Hint: First bit is 0 and its voltage level is negative to positive.

    Give your answer in the following table:

    0

    Question No.2

    Determine the following from the diagram given below:
    a9e2795b-7f36-4a92-88bc-e01f7475ee75-image.png
    • Period in Milliseconds
    • Frequency
    • Phase Shift

    Give your answer in the following table:

    Frequency Period Phase

    Question No. 3

    Suppose power P of a signal is increased 30 times after passing through an amplifier. By writing all necessary formulas and calculation steps, you are required to calculate amplification (power gain) in proper unit.

    Best of Luck!


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  • Cyberian's Gold


  • Cyberian's Gold

    Q. 1 Answer:

    0 1 1 0 0 1 0 0 1

    Q.2 Answer:

    Frequency Period Phase
    9 Hz =1/9 second =0.11 seconds = 110ms

    Q. 3 Answer:
    Suppose amplified signal is denoted as: P2 whereas P is the power of original signal.
    This means that P2 =30P
    Formula for calculating power gain is: 10 log10 P2/P
    By putting the values of P2 in the formula, we get
    =10 log10 30P/P =10 log10 30
    Value of log10 of 30 is around 1.4
    = 10(1.4) = 14 dB


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