CS609 Quiz #1 Solution and Discussion
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What is output of the following program;
#include<DOS.H> union REGS regs; void main (void ) { regs.h.al = 0x99; regs.h.ah = 0x00; printf ("%x",regs.x.ax); }
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@zaasmi
3 -
@moaaz
The circular keyboard buffer starts at the address 40:1EH and contains 32 bytes. The
address 40:1AH stores the head of this circular buffer while the address 40:1CH stores the
tail of this buffer. If the buffer is empty the head and tail points at the same location as
shown in the diagram above. -
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@zaasmi
32 bytes can be stored in Keyboard Buffer -
Total No. of bytes that can be stored in Keyboard Buffer is____.
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If we want to produce the shrill voice from the speaker phone then we have to load the ___ divisor value at Port ___.
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if the following function,
keep(1, 1000);
is called in the TSR program, it means that ________ No. of bytes are reserved in the memory. -
In counter register bit no. 3 changes its value between 0 and 1 with in ____clock cycles
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Parameters in interrupts are passed through _________ .
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Getting interrupt vector refers to the operation which is used to read the _________ address stored with in vector.
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Int86() has ________ parameters.
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If we want to send printing on the printer then we have to perform following steps.
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The address of partition block on hard disk is ___________________________.



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