CS609 Quiz #1 Solution and Discussion
-
What is output of the following program;
#include<DOS.H> union REGS regs; void main (void ) { regs.h.al = 0x99; regs.h.ah = 0x00; printf ("%x",regs.x.ax); }
-
-
@zaasmi
3
-
@moaaz
The circular keyboard buffer starts at the address 40:1EH and contains 32 bytes. The
address 40:1AH stores the head of this circular buffer while the address 40:1CH stores the
tail of this buffer. If the buffer is empty the head and tail points at the same location as
shown in the diagram above.
-
Ref: Page 55 Handout
-
@zaasmi
32 bytes can be stored in Keyboard Buffer
-
Total No. of bytes that can be stored in Keyboard Buffer is____.
-
If we want to produce the shrill voice from the speaker phone then we have to load the ___ divisor value at Port ___.
-
if the following function,
keep(1, 1000);
is called in the TSR program, it means that ________ No. of bytes are reserved in the memory.
-
In counter register bit no. 3 changes its value between 0 and 1 with in ____clock cycles
-
Parameters in interrupts are passed through _________ .
-
Getting interrupt vector refers to the operation which is used to read the _________ address stored with in vector.
-
Int86() has ________ parameters.
-
If we want to send printing on the printer then we have to perform following steps.
-
The address of partition block on hard disk is ___________________________.
