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STA304 GDB 1 Solution and Discussion

STA304 - Applied Statistics

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zaasmi Cyberian's Gold last edited by

Total Marks 5
Starting Date Thursday, May 28, 2020
Closing Date Friday, June 05, 2020
Status Open
Question Title Index Number
Question Description

How do we use Index Number in our daily life, explain it with an example and also mention the steps of construction of Index Number.

Note:

Don’t Paste the answer in MDB. This GDB is graded and marks will be awarded on its performance.

Note: Answer should be relevant. Irrelevant and unnecessary lengthy materials will not be considered.

Also it is strictly informed that the answer will not be received through emails.
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zaasmi Cyberian's Gold last edited by

37,33,33,32,29,28,23,22,22,22,21,21,20,20,19,19,18,18,18,18,16,15,14,14,14,12,12,9,6

Stream Leaf

0 9 6

1 9 9 8 8 8 8 6 5 4 4 4 2 2

2 9 8 8 3 2 2 2 1 1 1 0 0

3 7 3 3 2

Model Value 18
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Sameer took a loan of Rs 10,000 at the interest rate of 12% per annum for 5 years. Show that the compound interest is greater than simple interest on the given amount plz send me solution
CS315 Assignment 2 Solution and Discussion
CS315 - Network Security • cs315 assignment 2 solution discussion fall 2019 • • zareen

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@zareen said in CS315 Assignment 2 Solution and Discussion:

b) Number of keys being used for cryptography.

Although symmetric key cryptography makes use of only one key, asymmetric key cryptography, also known as public key cryptography, utilizes two keys: a public key and a private key. The public key is used to encrypt data sent from the sender to the receiver and is shared with everyone.

Public and Private Key Concept in Encryption

Secret key cryptography (symmetrical encryption): Both the sender and receiver must use the same key to encrypt and decrypt messages being sent. This imposes a security risk as we need to deliver the key to the recipient of the message in a secure way to make him/her able to decrypt the message. If an intruder gets hold of the key somehow, he/she will be able to decrypt the secret message and thus compromise the whole operation.

Public key cryptography (asymmetrical encryption): In this method we use two keys, one for encryption and the second for decryption. A user will use his/her friend’s public key to encrypt the message. The receiver will use a private key (which should be kept secret) in order to decrypt this message when needed. The public key is used to encrypt plain text or to verify a digital signature, whereas the private key is used to decrypt cipher text or to create a digital signature. Messages encrypted with the public key can only be decrypted using the associated private key pair.

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CS202 - Fundamentals of Front End Development • assignment 2 cs202 discussion solution spring 2020 • • zaasmi

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SOLVED CS502 Assignment No. 02 Solution and Discussion
CS502 - Fundamentals of Algorithms • cs502 assignment 2 solution discussion fall 2019 • • zareen

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Solution:
Question No. 01: The name of the algorithm being used for sorting the given array has given below.
Selection sort
Question No. 02: The Pseudo code for the algorithm used for sorting the given array has given below.

Pseudo code:
1 Selection sort (A)
{
2 For i 1 to A.lenght-1
{
3 imin i
4 for j i+1 to A.length
{
5 If (A[j] < A[imin])
Imin j
}
6 Temp A[i]
7 A[i] A[imin]
8 A[imin] Temp
}
}

Question No. 03: The step by stem analysis of the algorithm designed in question 2 is as follow,

The time taken by each statement (step) is given as follows,

b8c2d4d9-76e3-4841-94a7-e8c1a8202f51-image.png
Selection sort (A) Cost Times
{
For i 1 to A.length-1 |c1 | n
{
imin i--------------------> c2 n-1
for j i+1 to A.length
{ c3 n+n-1+…1=n(n+1)/2
If (A[j] < A[imin])
imin j
}
Temp A[i] c4 n-1
A[i] A[imin] c5 n-1
A[imin] Temp c6 n-1
}
}

Total time T(n) can be calculated as follows,

T(n)= c1n+c2(n-1)+c3(n(n+1)/2)+c4(n-1)+c5(n-1)+c6(n-1)
c1n+c2n-c2+c3 (n2+n/2) +c4n-c4+c5n-c5+c6n-c6 collect the like terms
c3n2/2+ (c1+c2+c3/2+c4+c5+c6) n + (-c2-c4-c5-c6)

This is equivalent to a polynomial an2+bn+c
Therefore T (n) = Big O (n2) by taking the highest order term of the equation.
Note: a, b, c in polynomial represents constants

// Ignoring constant terms

T(n) = O (n2)
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@zareen said in EDU304 Assignment 1 Solution and Discussion:

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Idea Solutionz
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