Operating Systems (CS604) Assignment # 03 Spring 2019 Total marks = 20 Deadline Date 23rd July, 2019 Please carefully read the following instructions before attempting assignment. RULES FOR MARKING It should be clear that your assignment would not get any credit if: ♣ The assignment is submitted after the due date. ♣ The submitted assignment does not open or file is corrupt. ♣ Strict action will be taken if submitted solution is copied from any other student or from the internet. You should consult the recommended books to clarify your concepts as handouts are not sufficient. You are supposed to submit your assignment in .doc or docx format. Any other formats like scan images, PDF, zip, rar, ppt and bmp etc will not be accepted. Objective: • The objective of this assignment is to provide hands on experience of: • To learn and understand deadlock algorithms in Operating System NOTE No assignment will be accepted after the due date via email in any case (whether it is the case of load shedding or internet malfunctioning etc.). Hence refrain from uploading assignment in the last hour of deadline. It is recommended to upload solution file at least two days before its closing date. If you find any mistake or confusion in assignment (Question statement), please consult with your instructor before the deadline. After the deadline no queries will be entertained in this regard. For any query, feel free to email at: cs604@vu.edu.pk Question No 1 15 Marks Consider the below given snapshot of the system. P1 to P5 represent the 5 processes currently running on the system. M, N, O and P represent the resources whereas M, N, O and P have 13, 11, 9 and 16 instances respectively. Considering the given snapshot, answer the following questions using the banker’s algorithm: (a) What will be the content of the matrix Available? 5 Marks (b) What will be the content of the matrix Need? 5 Marks © Is the system in a safe state Yes/No? If yes, then identify the safe sequence. 5 Marks Question No 2 5 Marks Consider the following resource allocation graph. Is there any deadlock in this graph or not? If yes, then mention the dead lock sequence.

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UNSOLVED CS604 Assignment # 03  Solution and Discussion

CS604 - Operating Systems

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zaasmi Cyberian's Gold last edited by

Operating Systems (CS604)
Assignment # 03 Spring 2019

Total marks = 20

Deadline Date   23rd July, 2019

Please carefully read the following instructions before attempting assignment.

RULES FOR MARKING
It should be clear that your assignment would not get any credit if:
♣ The assignment is submitted after the due date.
♣ The submitted assignment does not open or file is corrupt.
♣ Strict action will be taken if submitted solution is copied from any other student or from the internet.

You should consult the recommended books to clarify your concepts as handouts are not sufficient.

You are supposed to submit your assignment in .doc or docx format.
Any other formats like scan images, PDF, zip, rar, ppt and bmp etc will not be accepted.

Objective:
• The objective of this assignment is to provide hands on experience of:
• To learn and understand deadlock algorithms in Operating System

NOTE

No assignment will be accepted after the due date via email in any case (whether it is the case of load shedding or internet malfunctioning etc.). Hence refrain from uploading assignment in the last hour of deadline. It is recommended to upload solution file at least two days before its closing date.

If you find any mistake or confusion in assignment (Question statement), please consult with your instructor before the deadline. After the deadline no queries will be entertained in this regard.

For any query, feel free to email at:
[email protected]

Question No 1 15 Marks
Consider the below given snapshot of the system. P1 to P5 represent the 5 processes currently running on the system. M, N, O and P represent the resources whereas M, N, O and P have 13, 11, 9 and 16 instances respectively.

Considering the given snapshot, answer the following questions using the banker’s algorithm:
(a) What will be the content of the matrix Available? 5 Marks
(b) What will be the content of the matrix Need? 5 Marks
© Is the system in a safe state Yes/No? If yes, then identify the safe sequence. 5 Marks

Question No 2 5 Marks
Consider the following resource allocation graph. Is there any deadlock in this graph or not? If yes, then mention the dead lock sequence.
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CS101 Assignment 1 Solution and Discussion Fall 2020
CS101- Introduction to Computer • cs101 assignment 1 solution discussion fall 2020 assignment • • zareen

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@zareen said in CS101 Assignment 1 Solution and Discussion Fall 2020:

decimal numbers into equivalent binary numbers and then convert the binary
SOLVED CS604 GDB 1 solution and discussion
CS604 - Operating Systems • cs604 gdb1 solution spring 2019 • • zaasmi

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@zaasmi Mobile operating system like Android, ios, kindal, Bada, Black berry, Microsoft is an open mobile operating system with massive user/employee base and simplified mobile app development process. Enterprises are leveraging Android or etc and creating custom mobile apps that solves problems and increase value for their business. The mobile os is best for the organization because the every person have the smart phone, and the app is the Develop in low cost.
CS201 Assignment 3 Solution and Discussion
CS201 - Introduction to Programming • cs201 assignment 3 fall 2020 assignment • • laiba javed

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@zaasmi said in CS201 Assignment 3 Solution and Discussion:

Re: CS201 Assignment 3 Solution and Discussion

Assignment No. 3
Semester: Fall 2020
CS201 – Introduction to Programming Total Marks: 20
Due Date:
29-01-2021

Instructions
Please read the following instructions carefully before submitting assignment:
It should be clear that your assignment will not get any credit if:

o Assignment is submitted after due date.
o Submitted assignment does not open or file is corrupt.
o Assignment is copied (From internet/students).
o Assignment is not in .cpp format.

Software allowed to develop Assignment
Dev C++
Objectives:
In this assignment, the students will learn:
• Use of class in programming
• How to deal with a file in programming
• How to implement switch statement for Class based functions.

ABC bakery is using a console based inventory management system for the receipt generation purposes. Console application will help the cashier in calculating total price of each item with respect to its price. Menu list will provide Add an item option to take data about an inventory item, include Item Id, Item name, price and quantity. Relevant data of all items will be displayed on screen with the help of menu option. Quantity amount of items will changeable if user wants to add quantity of an item.

Problem Statement
Write a C++ program to manage the inventory item using your knowledge about file handling and classes. User will manage details of an Inventory item using menu list that will provide three options:

ENTER CHOICE
ADD AN INVENTORY ITEM DISPLAY FILE DATA INCREASE QUANTITY
Prompt will show to the user for continue the program after dealing with each option, until user will press a key other than ‘y’.

Instructions to write C++ program:

You will use class “Inventory” to declare inventory data and info
Make “Inventory.txt” file to save inventory item record
“Inventory.txt” file will delete each time when the program will run
“ERROE IN OPENING FILE” will be shown if user not press ‘1’ when program will execute first time.
You will use switch statement to handle different conditions and to perform different actions based on the different actions, that is, choice 1, 2, and 3.

Code structure [ Demonstration]:
You will be using the following class and other functions to develop the assignment:
class Inventory { private: int itemID; char itemName[20]; float itemPrice; float quantity; float totalPrice; public: void readItem(); void displayItem(); int getItemID() ; float getPrice() ; float getQuantity() ; void updateQuantity(float q); }; //Deleting existing file void deleteExistingFile(){--------} //Appending item in file void appendToFille(){------------} //Displaying items void displayAll(){------------} //Increasing Quantity of item void increaseQuanity(){------------}
Program Output:

User’s prompt when program will execute for the first time.
6bcfa578-bdbb-4d1a-afd3-1f50ec8dd32b-image.png

When user press ‘1’ , It will take data about an inventory item as an input from the user.
02679a3e-f114-43f3-b38a-0f9596a53d86-image.png

When user press ‘2’, it will read data from “Inventory.txt” file and display record of all inventory items on the screen
fc208996-9a2a-44fa-ad1e-c4734f3368ab-image.png

If user press ‘3’, it will ask to enter Item id against which user want to increase item quantity.
799bf532-032e-4891-bac8-795fefea34b5-image.png

Now, when the user will press ‘2’, the inventory item record will be shown as:
559a0b14-878a-400f-a916-a2ce8fd4e3fc-image.png

Assignment#3 covers course contents from lecture 17 to 30.

Best of Luck!

#include<iostream> #include<fstream> #include<stdio.h> using namespace std; class Inventory { private: int itemID; char itemName[20]; float itemPrice; float quantity; float totalPrice; public: void readItem(); void displayItem(); int getItemID() { return itemID;} float getPrice() { return itemPrice;} float getQuantity() { return quantity;} void updateQuantity(float q) { quantity=q; totalPrice = (itemPrice*quantity); } }; // Getting Item void Inventory::readItem(){ cout << "Please enter item id: "; cin >> itemID; cout << "Please enter item name: "; cin.ignore(1); cin.getline(itemName,20); cout << "Please enter price: "; cin >> itemPrice; cout << "Please enter quantity: "; cin >> quantity; totalPrice = (itemPrice*quantity); } // Displaying Item void Inventory::displayItem() { cout << "Item id:" << itemID << "\tItem name:" << itemName << "\t ItemPrice:" << itemPrice << "\t Quantity:" << quantity << "\t TotalPrice:" << totalPrice << endl; } // Deleting existing file void deleteExistingFile(){ remove("Inventory.txt"); } // Appending item in file void appendToFille(){ Inventory x; x.readItem(); ofstream file; file.open("Inventory.txt",ios::binary | ios::app); if(!file){ cout << "ERROR WHILE CREATING A FILE!\n"; return; } file.write((char*)&x,sizeof(x)); file.close(); cout<<"Inventory record(s) added sucessfully.\n"; } // Displaying items void displayAll(){ Inventory x; ifstream file; file.open("Inventory.txt",ios::binary | ios::in); if(!file){ cout<<"ERROR IN OPENING FILE \n"; return; } while(file){ if(file.read((char*)&x,sizeof(x))) x.displayItem(); } file.close(); } // Increasing Quantity of item void increaseQuanity(){ int itemValue; int isFound=0; int q; Inventory x; cout<<"Enter item id: \n"; cin >> itemValue; ifstream fileRead; fileRead.open("Inventory.txt",ios::binary | ios::in); if(!fileRead){ cout<<"ERROR IN OPENING FILE \n"; return; } while(fileRead){ if(fileRead.read((char*)&x,sizeof(x))){ if(x.getItemID() == itemValue){ cout << "Add quantity? "; cin >> q; x.updateQuantity(x.getQuantity() + q); isFound=1; break; } } } if(isFound==0){ cout<<"Record not found!!!\n"; } fileRead.close(); deleteExistingFile(); ofstream fileWrite; fileWrite.open("Inventory.txt",ios::binary | ios::app); fileWrite.write((char*)&x,sizeof(x)); fileWrite.close(); cout << "Item Quantity updated successfully."<<endl; } int main() { char ch; do { char n; cout << "ENTER CHOICE\n" << "1. ADD AN INVENTORY ITEM\n" << "2. DISPLAY FILE DATA\n" << "3. INCREASE QUANTITY\n"; cout << "Please select a choice: "; cin >> n; switch(n) { case '1': appendToFille(); break; case '2' : displayAll(); break; case '3': increaseQuanity(); break; default : cout << "Invalid Choice\n"; break; } /* else cout<<"Enter integer value only"; } */ cout << "Do you want to continue? : "; cin >> ch; } while(ch=='Y'||ch=='y'); return 0; }
SOLVED CS604 Assignment 1 Solution and Discussion
CS604 - Operating Systems • cs604 assignment 1 solution discussion fall 2019 • • zareen

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Solution:
Q. 1 Answer:
As a process executes, it changes states. The state of a process is defined in part by the current activity of that process. Given below are current and next states of process. According to your understanding, what can be condition that changes one state into another:
Sr # Current State -> Next State Conditions 1 Ready->Running Scheduler Dispatch 2 Waiting->Ready I/O or Event Completion 3 Running->Terminated Exit 4 Running->Ready Interrupt 5 New->Ready Admitted
Q.2 Answer:
The following table contains the list of operations. Write down the Linux commands along with their screenshots for performing these operations:
List of Operations List the contents of files to the terminal window. Change the owner and group owner of a file. Compares two text files and show the differences between them Print a string of text to the terminal window. Change the password for a user.
You are required to run the respective commands on Ubuntu and provide relevant screen shots of the list of operations as stated in above table.
Sr # List of Operations Command 1 List the contents of files to the terminal window. cat 2 Change the owner and group owner of a file. chown 3 Compares two text files and show the differences between them diff 4 Print a string of text to the terminal window. echo 5 Change the password for a user. passwd
CS304 Assignment 1 Solution and Discussion Fall 2020
304 - Object Oriented Programming • cs304 assignment 1 solution discussion fall 2020 assignment • • zaasmi

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Operating Systems (CS604) Assignment # 02  Spring 2019 Solution and Discussion
CS604 - Operating Systems • • zaasmi

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ECO406 Assignment 1 Solution and Discussion
ECO406 - Mathematical Economics • eco406 assignment 1 solution discussion fall 2020 assignment • • majid bhatti

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SOLVED CS604 Assignment 2 Solution and Discussion
CS604 - Operating Systems • cs604 solution discussion fall 2019 assignment 2 • • zareen

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Solution:
Q. 1 Answer
P0 P4 P3 P2 P1 P5 0 2 5 9 10 16 24
Total Waiting Time = 0+2+5+1+10+16 = 34 Seconds
Average Waiting Time = 34/6 = 5.66 Seconds

Q.2 Answer:
Solution 1:
P0 P1 P3 P0 P2 P3 P2 P3 P2 P2 0 8 16 24 31 39 47 55 57 65 66
Turnaround time= Exit Time- Arrival Time

Turnaround time for P0 = 31-0 = 31
P1 = 16-4 = 12
P2 = 66-18 = 48
P3 = 57- 5= 52

Total Turnaround Time = 39+12+48+52 = 143
Average Turnaround Time = 143 / 4 =35.75 millisecond

Waiting Time= Turnaround Time- Burst Time

Waiting time for P0 = 31-15 = 16
P1 = 12-8 = 4
P2 = 48-25 = 23
P3 = 52-18 = 34

Total Waiting Time = 16+4+23+34 =77
Average Waiting Time = 77 / 4 =19.25 millisecond

Solution 2:
P0 P1 P3 P2 P0 P3 P2 P3 P2 P2 0 8 16 24 31 39 47 55 57 65 66
Turnaround time= Exit Time- Arrival Time

Turnaround time for P0 = 39-0 = 39
P1 = 16-4 = 12
P2 = 66-18 = 48
P3 = 57- 5= 52

Total Turnaround Time = 39+12+48+52 = 151
Average Turnaround Time = 151 / 4 =37.75 millisecond

Waiting Time= Turnaround Time- Burst Time

Waiting time for P0 = 39-15 = 24
P1 = 12-8= 4
P2 = 48-25= 23
P3 = 52-18 = 34

Total Waiting Time = 24+0+5+29 = 85
Average Waiting Time = 85 / 4 =21.25 millisecond

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UNSOLVED CS604 Assignment # 03 Solution and Discussion

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UNSOLVED CS604 Assignment # 03  Solution and Discussion

CS101 Assignment 1 Solution and Discussion Fall 2020
CS101- Introduction to Computer • cs101 assignment 1 solution discussion fall 2020 assignment • • zareen

SOLVED CS604 GDB 1 solution and discussion
CS604 - Operating Systems • cs604 gdb1 solution spring 2019 • • zaasmi

CS201 Assignment 3 Solution and Discussion
CS201 - Introduction to Programming • cs201 assignment 3 fall 2020 assignment • • laiba javed

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CS604 - Operating Systems • cs604 assignment 1 solution discussion fall 2019 • • zareen

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Operating Systems (CS604) Assignment # 02  Spring 2019 Solution and Discussion
CS604 - Operating Systems • • zaasmi

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ECO406 - Mathematical Economics • eco406 assignment 1 solution discussion fall 2020 assignment • • majid bhatti

SOLVED CS604 Assignment 2 Solution and Discussion
CS604 - Operating Systems • cs604 solution discussion fall 2019 assignment 2 • • zareen