MTH603 Grand Quiz Solution and Discussion
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Under iterative methods, the initial approximate solution is assumed to be………….
Known
UnKnown
Found
No of the given -
@zaasmi said in MTH603 Grand Quiz Solution and Discussion:
Under iterative methods, the initial approximate solution is assumed to be………….
In computational mathematics, an iterative method is a mathematical procedure that uses an initial guess to generate a sequence of improving approximate …
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While using the Gauss-Seidel Method for finding the solution of the following system
2x+2y+z=3
x+3y+z=2
x+y+z=2with the initial guess (0,0,0), the next iteration would be
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Differences methods are iterative methods.
True
False -
@zaasmi said in MTH603 Grand Quiz Solution and Discussion:
Differences methods are iterative methods.
In computational mathematics, an iterative method is a mathematical procedure that uses an initial guess to generate a sequence of improving approximate …
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@zaasmi said in MTH603 Grand Quiz Solution and Discussion:
@zaasmi said in MTH603 Grand Quiz Solution and Discussion:
Differences methods are iterative methods.
In computational mathematics, an iterative method is a mathematical procedure that uses an initial guess to generate a sequence of improving approximate …
False
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Which of the following system of equation is diagonally dominant?
2x+13y+5z=7
8x+y−z=5
x+2y+9z=38x+y−z=5
2x+13y+5z=7
x+2y+9z=3x+2y+9z=3
8x+y−z=5
2x+13y+5z=78x+y−z=5
x+2y+9z=3
2x+13y+5z=7 -
The 2nd row of the augmented matrix of the system of linear equations is:
2x+z=4
x-y+z=-3
-y+z=-51,-1, 0 and -3
1,-1, 1 and -3
1,-1, 0 and 3
1,-1, 0 and -5 -
While using Relaxation method, which of the following is the largest Residual for 1st iteration on the system;
2x+3y = 1, 3x +2y = - 4 ?
-4
3
2
1 -
While using power method, the computed vector
u(2)=⎛⎝⎜⎜5.5714289.5714212.21423⎞⎠⎟⎟
will be in normalized form as -
If
A=⎡⎣⎢⎢0131410−13⎤⎦⎥⎥
then by using Gaussian Elimination method the value of
A−1
will be -
While using the Gauss-Seidel Method for finding the solution of the following system
3x+y+z=11
2x+5y−z=16
x+y+5z=4with initial guess (0,0,0), the next iteration would be
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If A=⎡⎣⎢⎢⎢⎢⎢231024039⎤⎦⎥⎥⎥⎥⎥then by using Gaussian Elimination method the value of A−1 will be
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While using Jacobi method for the matrix
A=⎡⎣⎢⎢200021012⎤⎦⎥⎥
the value of ‘theta θ’ can be found as