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MCM401 GDB 1 Solution and Discussion

zareen Cyberian's Gold last edited by
Total Marks 5
Starting Date Wednesday, January 08, 2020
Closing Date Thursday, January 09, 2020
Status Open
Question Title Advertising in PR
Question Description

Topic/Area for Discussion

Advertising in PR

Ethics is the most important feature of the advertising industry. Though there are many benefits of advertising but then there are some points which don’t match the ethical norms of advertising. An ethical ad is the one which doesn’t lie, doesn’t make fake or false claims and is in the limit of decency.

Do you think advertising has changed over time and now it lacks principles of advertising ethics like false claims, indecent language or gestures, obscenity?

Important Instructions:
```
Your discussion must be based on logical facts.
Your answer should be in between 300-500 words.
Use the font style “Times New Roman” and font size “12”.
Your answer should be relevant to the topic i.e. clear and concise.
```
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SOLVED CS302 Assignment 2 Solution and Discussion
CS302 - Digital Logic Design • solution discussion fall 2019 assignment 2 cs302 • • zareen

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ASSIGNMENT NO:2
Course: CS302
1: Write the SOP expression for the given sum.

Sol:
A B C D E
0 0 0 0 0
0 0 0 0 1
0 0 0 1 0
0 0 0 1 1
0 0 1 0 0
0 0 1 0 1
0 0 1 1 0
0 0 1 1 1
0 1 0 0 0
0 1 0 0 1
0 1 0 1 0
0 1 0 1 1
0 1 1 0 0
0 1 1 0 1
0 1 1 1 0
0 1 1 1 1
1 0 0 0 0
1 0 0 0 1
1 0 0 1 0
1 0 0 1 1
1 0 1 0 0
1 0 1 0 1
1 0 1 1 0
1 0 1 1 1
1 1 0 0 0
1 1 0 0 1
1 1 0 1 0
1 1 0 1 1
1 1 1 0 0
1 1 1 0 1
1 1 1 1 0
1 1 1 1 1

A B C D E OUTPUT
(F)
0 0 0 0 0 0
0 0 0 0 1 0
0 0 0 1 0 1
0 0 0 1 1 0
0 0 1 0 0 1
0 0 1 0 1 0
0 0 1 1 0 1
0 0 1 1 1 0
0 1 0 0 0 1
0 1 0 0 1 0
0 1 0 1 0 1
0 1 0 1 1 0
0 1 1 0 0 1
0 1 1 0 1 0
0 1 1 1 0 1
0 1 1 1 1 0
1 0 0 0 0 1
1 0 0 0 1 0
1 0 0 1 0 1
1 0 0 1 1 0
1 0 1 0 0 1
1 0 1 0 1 0
1 0 1 1 0 1
1 0 1 1 1 0
1 1 0 0 0 1
1 1 0 0 1 0
1 1 0 1 0 1
1 1 0 1 1 0
1 1 1 0 0 1
1 1 1 0 1 0
1 1 1 1 0 1
1 1 1 1 1 0
FOR SOP WE FOCUS ON 1 VALUE.
A B C D E MINTERM
0 0 0 1 0

0 0 1 0 0

0 0 1 1 0

0 1 0 0 0

0 1 0 1 0

0 1 1 0 0

0 1 1 1 0

1 0 0 0 0

1 0 0 1 0

1 0 1 0 0

1 1 1 0 0

1 1 0 0 0

1 1 0 1 0

1 1 1 0 0

1 1 1 1 1 ABCDE

SOP EXPRESSION:
SUM OF PRODUCT EXPRESSION

2: Find Prime Implicant of minterm using QuineMcculsky method.

Step-1
00010 2
00100 4
01000 8
10000 16
00110 6
01010 10
01100 12
10010 18
10100 20
11000 24
01110 14
10110 22
11010 26
11100 28
11110 30

Step-2
2,6(00-10) 2,10(0-010) 2,18(-0010)
4,12(0-100) 4,6(001-0) 4,20(-0100)
8,10(010-0) 8,24(-1000)
16,18(100-0) 16,20(10-00) 16,24(10-00)
6,14(0-110) 6,22(-0110)
10,14(01-10)10,26(-1010)
12,14(011-0) 12,28(-1100)
18,26(1-010) 18,22(10-10)
20,22(101-0) 20,22(1-100)
24,26(110-0) 24,28(11-00)
14,30(-1110) 22,30(1-110) 26,30(11-10) 28,30(111-0)
Step-3
2,6,18,22(-0-10) 2,6,10,14( 0–10)2,10,18,26(–010)2,18,6,22(-0-10)
2,18,10,26(–010)4,12,6,14(0-1-0) 4,6,12,14 (0-1-0)
4,6,20,22(-01-0)4,20,6,22(-01-0) 4,20,12,28(–100) 8,10,12,14(01–0) 8,24,10,26(-10-0) 8,24,12,28 (-1-00)
6,14,22,30 (–110) 6,22,14,30(–110) 10,14,26,30(-1-10) 10,26,14,30(-1-10) 12,14,28,30(-11-0) 12,14,28,30(-11-0)
18,26,22,30(1–10) 18,22,26,30(1–10) 20,22,28,30(1-1-0)
20,22,22,30(1-1-0) 24,26,28,30(11–0) 24,28,26,30(11–0)
Step-3
2,6,18,22(-0-10) 4,6,20,22(-01-0)
2,18,10,22(-0-10) 4,20,6,22(-01-0)
2,10,18,26(–010) 4,12,6,14(0-1-0)
2,18,6,22(–010) 4,6,12,14 (0-1-0)
4,20,12,28(–100) 10,14,26,30(-1-10)
6,14,22,30 (–110) 10,26,14,30(-1-10)
12,14,28,30(-11-0) 18,26,22,30(1–10)
12,14,28,30(-11-0) 18,22,26,30(1–10)
20,22,28,30(1-1-0) 24,26,28,30(11–0)
20,22,22,30(1-1-0) 24,28,26,30(11–0)
6,22,14,30(–110)
8,10,12,14(01–0)
8,24,12,28 (-1-00)
8,24,10,26(-10-0)
Step-4
2,6,8,22(-0-10) 4,6,20,22(-01-0)
2,10,18,26(–010) 4,12,6,14(0-1-0)
4,20,12,28(–100) 10,14,26,30(-1-10)
12,14,28,30(-11-0) 18,26,22,30(1–10)
20,22,28,30(1-1-0) 24,26,28,30(11–0)
6,22,14,30(–110) 8,10,12,14(01–0)
8,24,12,28 (-1-00) 8,24,10,26(-10-0)
These are the prime implicates
cs302-assign 2.docx
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@zareen
Throughout history, both small and large nations have elevated certain types of nonelected workers to positions of relative power within the governmental structure. Collectively, these essential workers are called the bureaucracy. A bureaucracy is an administrative group of nonelected officials charged with carrying out functions connected to a series of policies and programs. In the United States, the bureaucracy began as a very small collection of individuals. Over time, however, it grew to be a major force in political affairs. Indeed, it grew so large that politicians in modern times have ridiculed it to great political advantage. However, the country’s many bureaucrats or civil servants, the individuals who work in the bureaucracy, fill necessary and even instrumental roles in every area of government: from high-level positions in foreign affairs and intelligence collection agencies to clerks and staff in the smallest regulatory agencies. They are hired, or sometimes appointed, for their expertise in carrying out the functions and programs of the government.
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Ideas Solution Code
#include <iostream> #include <time.h> #include <stdlib.h> using namespace std; const int rows = 10; const int cols = 10; int selectOption(){ int choice = 0; cout<<"Press 1 to populate a two-dimensional array with integers from 1 to 100\n"; cout<<"Press 2 to display the array elements\n"; cout<<"Press 3 to display the largest element present in the array along with its row and column index\n"; cout<<"Press 4 to find and show the transpose of the array\n"; cout<<"Press 5 To Exit\n"; cout<<"\nPlease select an option, use numbers from 1 to 5: "; do { cin>>choice; if(choice >= 1 && choice <= 5){ break; } else { cout<<"\nChoice should be between 1 and 5\n"; cout<<"Invalid choice, please select again: "; } } while(true); cout<<"___________________________________________________\n"; return choice; } // end selectOption function void populateArray(int data[rows][cols]){ srand(time(0)); for(int i = 0; i < rows; i++){ for(int j = 0; j < cols; j++){ data[i][j] = rand() % 100 + 1; } } cout<<"Array populated sucessfully\n"; } // end of poulateArray function void showElements(int data[rows][cols]){ for(int i = 0; i < rows; i++){ for(int j = 0; j < cols; j++){ cout<<data[i][j]<<"\t"; } cout<<endl; } } // end of showElements function void showLargestElement(int data[rows][cols]){ int largest = 1, row =0, col = 0; for(int i = 0; i < rows; i++){ for(int j = 0; j < cols; j++){ if(data[i][j] > largest){ largest = data[i][j]; row = i; col = j; } } } cout<<"Largest element is "<<largest<<" which is at row = "<<row+1<<" or index = "<<row<<" and column "<<col+1<<" or index "<<col<<endl; } // end of showLargestElement function void transposeArray(int data[rows][cols]){ for(int i = 0; i < cols; i++){ for(int j = 0; j < rows; j++){ cout<<data[j][i]<<'\t'; } cout<<endl; } } // end of transposeArray function main(){ int choice = 0, data[rows][cols] = {0}; do{ choice = selectOption(); switch(choice){ case 1: cout<<endl; populateArray(data); cout<<endl; break; case 2: if(data[0][0] == 0){ cout<<"\nSorry the array is empty, first populate it by pressing 1 to perform this task"<<endl<<endl<<endl; continue; } cout<<endl; showElements(data); cout<<endl; break; case 3: if(data[0][0] == 0){ cout<<"\nSorry the array is empty, first populate it by pressing 1 to perform this task"<<endl<<endl<<endl; continue; } cout<<endl; showLargestElement(data); cout<<endl; break; case 4: if(data[0][0] == 0){ cout<<"\nSorry the array is empty, first populate it by pressing 1 to perform this task"<<endl<<endl<<endl; continue; } cout<<endl; transposeArray(data); cout<<endl; break; } }while(choice != 5); // end of do-while loop } // end of main function
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