SOLVED MTH603 Assignment 1 Solution and Discussion
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Assignment NO. 1 MTH603 (Fall 2019)
Maximum Marks: 20 Due Date: 24 -11-2019
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• Also remember that you are supposed to submit your assignment in Word format any other like scan images etc. will not be accepted and we will give zero mark corresponding to these assignments.Question #1: Find the root of the equation, Perform three iteration of the equation,
ln (x −1) + sinx = 0 by using Newton Raphson method.
Question #2: Solve the system of linear equations with the help of Gaussian elimination method.
x + y + z = 6; 2x − y + z = 3; x + z = 4 -
Assignment No: 01
Question #1: Find the root of the equation, Perform three iteration of the equation,
ln (x −1) + sinx =0 by using Newton Raphson method.Ans: Let f(x) = ln(x+1) + sinx = 0 and f(x) = 1/(x-1) + cosx
F (1.5) = ln(0.5) + (1.5) = - 0.0667
F(2) = ln(1) + sin(2) = 0.035
Since f (1.5) f (2) < 0 so roots lies in interval [1.5, 2]
Let x0 = 1.75 . x0 can be taken in the interval any real number [ 1.5 , 2 ], we let mid point
of this interval .
As we know Newton Raphson method isXn+1 = xn – f ( xn ) / f(xn)
First iteration
X1 = x0 –f(x0) / f(x0) = 1.75 - f(1.75) / f(1.75)
= 1.75 – (-0.2571 / 2.3329) = 1.8602
Second iteration:
X2 = x1 - f(x) / f(x) = 1.8602 –[ f(1.8602) / f(1.8602)]
= 1.8602 - ( -0.1181 / 2.1620 ) = 1.9148
Third iteration:
X3 = x2- f(x2) / f(x2) = 1.9148 –f(1.9148) / f(1.9148)
= 1.9148 – [-0.0556/2.0926]
= 1.9414
Question #2: Solve the system of linear equations with the help of Gaussian elimination method.
x + y + z = 6;2x − y + z = 3;x + z = 4ANS: In Gaussian elimination method we convert the augmented matrix into reduce
Echelon form therefore,
Augmented matrix is
R2- 2R1 , R3 – R1
-1R2 , -1R3
R23
R3-3R2X + Y+ Z = 6 ;………………….(1)
Y = 2,
Z = 3
Put into eq (1),
we get X = 1 , -
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