@zareen said in CS101 Assignment 1 Solution and Discussion Fall 2020:
decimal numbers into equivalent binary numbers and then convert the binary
Digital Logic Design (CS302)
Assignment # 01
Total marks = 20
Deadline:01-06-2020
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Topic Covered:
Number Systems
Octal number
BCD Numbers
Lectures Covered
Lecture 01- 06
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Questions No 01 Marks (05)
Perform decimal to binary conversion on given decimal number using Sum-of-weights method. Verify the answer using repeated division method.
Decimal Number=1050
Questions No 02 Marks (10)
Perform the following arithmetic operations. For conversion you can use indirect method of conversion only.
〖(E2BC3F)〗_16-(10110101000000011110001)_2+ (537476217)_8 =(________)_16
Questions No 03 Marks (05)
Perform BCD addition between these two numbers. Kindly perform all the steps.
46
37
@zaasmi said in CS302 Assignment 1 Solution and Discussion:
Questions No 02 Marks (10)
Perform the following arithmetic operations. For conversion you can use indirect method of conversion only.
〖(E2BC3F)〗_16-(10110101000000011110001)_2+ (537476217)_8 =(________)_16
Questions No 03 Marks (05)
Perform BCD addition between these two numbers. Kindly perform all the steps.
46
37
0101 1010 1000 0000 1111 0001
5 A 8 0 F 1
(537476217)_8=(101 011 111 100 111 110 010 001 111)_2
Again, as we use 4-bits to represent a Hexadecimal Number, we have to rearrange the stated Binary Number.
(101 011 111 100 111 110 010 001 111)_2=(0101 0111 1110 0111 1100 1000 1111)_2
=5 7 E 7 C 8 7
(537476217)_8= (101 011 111 100 111 110 010 001 111)_2=(57E7C8F)_16
By performing the stated arithmetic operations on given three Hexadecimal Number System, we will get the final Answer.
〖(E2BC3F)〗_16-(10110101000000011110001)_2+ (537476217)_8 =(606B7DD)_16
@zaasmi said in CS302 Assignment 1 Solution and Discussion:
Questions No 01 Marks (05)
Perform decimal to binary conversion on given decimal number using Sum-of-weights method. Verify the answer using repeated division method.
Decimal Number=1050
Sum of Term | Highest Weight | Binary Number | Sum of Term – Highest Weight |
1050 | 1024 | 10000000000 | 26=1050-1024 |
26 | 16 | 10000100000 | 10=26-16 |
10 | 8 | 10000011000 | 2=10-8 |
2 | 2 | 10000011010 | 0=2-2 |
Binary Equivalent= (10000011010)2
Repeated Division Method:
2 | 1050 |
2 | 525-0 |
2 | 262-1 |
2 | 131-0 |
2 | 65-1 |
2 | 32-1 |
2 | 16-0 |
2 | 8-0 |
2 | 4-0 |
2 | 2-0 |
1-0 |