# CS314 Assignment 1 Solution and Discussion

• Assignment No. 01
Semester: Spring 2020
CS314: Introduction to Cellular Networks Total Marks: 20

Due Date:
29th of May 2020

Instructions:
You need to use MS word document to prepare and submit the assignment on VU-LMS.
It should be clear that your assignment will not get any credit if:

 The assignment is submitted after due date.
 The assignment is not in the required format (doc or docx).
 The submitted assignment does not open or file is corrupt.
 Assignment is copied (partial or full) from any source (websites, forums, students, etc).

Objectives:
The objective of this assignment is to increase the learning capabilities of the students about:

• Frequency Planning
• Cell Pattern
• Channels Distribution
• Network Cells

Assignment

Question – 1 10 Marks
Consider a certain Cellular network system in which we had used frequency-based division duplexing mechanism. The total assigned bandwidth of the system is 100 MHz, whereas the network uses 30 KHz channel for full duplex communication. In view of this, you are required to calculate the following:

1. The complete channel bandwidth.
2. The maximum no. of channels available.
3. The no. of required channel per cell in a cluster having i= 3 & j = 2.

Note: All calculation steps and formulas carry marks. So, you need to write every step involved with justifications wherever required.

Question – 2 10 Marks
Suppose we had an area covered using 10 Cells. Assume that during a busy hour, the number of calls per hour (Qi) for each 10 cells is given as :
2000, 1500, 1300, 1000, 1900, 400, 670, 1300, 1900 and 2100.

Let us assume that 60 percent of the car phones will be used during this period (ηc = 0.6) and that one call is made per car phone.

You are required to calculate the total no of calls made in stated hour. Also calculate the total number of customers in the system.

Note: All calculation steps and formulas carry marks. So, you need to write every step involved with justifications wherever required.

• The complete channel bandwidth.

Bandwidth is a fixed quantity, so it cannot be changed. Hence, the channel capacity is directly proportional to the power of the signal, as SNR = (Power of signal) / (power of noise). so for example a signal-to-noise ratio of 1000 is commonly expressed as: 10 * log10(1000) = 30 dB.

Capacity = bandwidth * log2(1 + SNR)

Output1 : C = 30000 * log2(1 + SNR) = 30000 * 11.62 = 348600 bps  1

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