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CS610 GDB 1 solution and discussion

CS610 - Computer Networks

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A company ABC wants a medium-sized network spread within the city consisting of around 100 LANs in different buildings across the city.

Every building is also divided into several different departments (segments) and all the departments should be connected to ensure real-time communication and data sharing.

The key requirements of the company are:
1. Fast convergence of the network upon adding/removing a new network.
2. Fastest possible delivery of data from source to destination.
As a network administrator, you are required to select the pair of required devices for the network and routing algorithm to fulfill the requirements of the company.

Devices:

Router and Bridge
Repeater and Router
Bridge and Repeater

Algorithms:

Distance Vector Routing Algorithm
Link State Routing

Justify your selection of Devices and Algorithm with solid reasons.
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Q.1. Solution
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Q.2. Solution
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Solution Idea!
#include <bits/stdc++.h> using namespace std; class HeapNode_Min { // Tree node of Huffman public: //Add data members here. char d; unsigned f; HeapNode_Min *l, *r; HeapNode_Min(char d, unsigned f = -1) { //Complete the body of HeapNode_Min function this->d = d; this->f = f ; this->l = NULL; this->r = NULL; } }; class Analyze { // two heap nodes comparison public: bool operator()(HeapNode_Min* l, HeapNode_Min* r) { //add return before statement and statement is completed. return (l->f > r->f); //Complete this statement } }; void display_Codes(HeapNode_Min* root, string s) // To print codes of huffman tree from the root. { if (!root) return; if (root->d != '$') cout root->d "\t: " s "\n"; display_Codes(root->l, s + "0"); display_Codes(root->r, s + "1"); //Complete this statement by passing arguments } void HCodes(char data[], int freq[], int s) // builds a Huffman Tree { HeapNode_Min *t,*r, *l ; // top, right, left priority_queue<HeapNode_Min*, vector<HeapNode_Min*>, Analyze> H_min; int a=0; while (a<s){H_min.push(new HeapNode_Min(data[a], freq[a])); ++a;} while (H_min.size() != 1) { l = H_min.top(); H_min.pop(); r = H_min.top(); H_min.pop(); t = new HeapNode_Min('$', r->f + l->f); t->r = r; t->l = l; H_min.push(t); } display_Codes(H_min.top(), ""); } int main() { int frequency[] = { 3, 6, 11, 14, 18, 25 }; char alphabet[] = { 'A', 'L', 'O', 'R', 'T', 'Y' }; //Complete this statement by passing data type to both sizeof operators int size_of = sizeof(alphabet) / sizeof(*alphabet); cout"Alphabet"":""Huffman Code\n"; cout"--------------------------------\n"; //Call Huffman_Codes function. HCodes(alphabet, frequency, size_of); return 0; }
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Use the caesar cipher method to encrypt the word “ACTIVATION” and show the complete process step by step.

A B C D E F G H I K L M N O P Q R S T U V W X Y Z

Chose a number form 1 to 26 .the number will represent the key or the “shift” value that will be used to shift the standard Alphabet.

KEY= 4

A B C D E F G H I K L M N O P Q R S T U V W X Y Z

W X Y Z A B C D E F G H I K L M N O P Q R S T U V

Now bottom row of ALPHABE will now by known as Cipher ALPHABET.

KEY=4

Message =”ACTIVATION”

Plain : A B C D E F G H I K L M N O P Q R S T U V W X Y Z

Cipher: W X Y Z A B C D E F G H I K L M N O P Q R S T U V

Ciper text : WYPERWPEKI

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CS610 GDB 1 solution and discussion

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