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MCD403 GDB 1 Solution and Discussion

MCD403 - Music Production

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zareen Cyberian's Gold last edited by

Folk music is a true representative of cultural and regional traditions of Pakistan. Elaborate. Also mention few instruments that are strongly associated to our folk music.
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Sometimes employee’s performance is highly based on his/her ability to perform; in such situations salaries are based on employee competency. This type of salaries is termed as:
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Unlike the Classical economists, Keynes believed that the economy could get stuck in the short run for a significant period of time because:
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SOLVED MCD403 Assignment 1 Solution and Discussion
MCD403 - Music Production • mcd403 assignment 1 solution discussion fall 2019 • • zareen

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Q.1 Solution:
Camera Jib:
Device that’s come into wide use in the last decade is the camera jib, essentially a long, highly maneuverable boom or crane-like device with a mounted camera at the end. You frequently see them in action swinging overhead at concerts and major events. A jib allows sweeping camera movements from ground level to nine meters (thirty feet) or more in the air.
Camera Copters/ Drone Cameras
Since remotely-controlled, helicopter-type drones can move into places inaccessible by individuals or fixed-wing aircraft, they can provide coverage of events otherwise unattainable. Plus, helicopter type drones can hover above news scenes for extended periods of time. The video signal is relayed (live) to a receiver on the ground.

Q.2 Differentiate the below given camera movements while giving an example of each.
・ Dolly
・ Trucking
Answer:
We refer to moving (rolling) the entire camera toward or away from the subject as a dolly (“dolly in” for a close shot or “dolly back” for a wide-shot).
A lateral move (rolling the camera to the left or right on the pedestal) is trucking, as in “truck left” or “truck right.”
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Grand Quiz Syllabus and Schedule
Dear Students,
Assalam-o-Alaikum!

Due to the prevailing circumstances, Grand Quiz will be conducted to replace Proctored Mid-Term Exam in this course of MGT201. You can attempt Grand Quiz within 24 Hours. So it is advised to be proactive since there will be no extension.
Number of Questions 30 Weightage 20% Types of Questions MCQs Opening Date Dec 28, 2020 at 12:00 AM Closing Date Dec 28, 2020 at 11:59 PM Lessons Video Lecture 1-22
Special Instructions

You must attempt your Grand Quiz effectively as it is being held as your mid-term exam and it would be equivalent to 20% of the overall course weightage.

You can start attempting the quiz at any time but within given date(s) by clicking the quick link for Quiz on VU-LMS as it will become enabled within the mentioned dates. As soon as the time will be over, it will automatically be disabled and will not be available to attempt it.

Please note that some questions of the quiz may require some computation as well. So plan your course preparation accordingly.

Each question has maximum time limit of 90 seconds to attempt and save. So, you have to save your answer before 90 seconds. But due to unpredictable/unstable Internet speed, it is strongly recommended that you save your answer within 60 seconds to avoid any inconvenience. While attempting a question, keep an eye on the remaining time.

Attempting quiz is unidirectional. Once you have moved forward to the next question, you will not be able to go back to the previous one. Therefore, before moving to the next question, make sure that you have selected the best option and have saved your answer.

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If for any reason, you lose access to Internet (like power failure or disconnection of Internet); you will be able to attempt the quiz again but from the next question where you left in the last attempt. But remember that you have to complete the quiz before expiry of the deadline.

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#include<iostream> using namespace std; class TNode{ private: node* root; public: TNode(); int isEmpty(); void buildTree(int item); void insert(int item,node *,node *); void minNode(node*); void maxNode(node*); int countNodes(node*); int treeHeight(node*); void displayBinTree(); }; TNode::TNode(){ root = NULL; } int TNode::isEmpty() { return (root == NULL); } void TNode::buildTree(int item){ node *p = new node; node *parent; cout <<"Insert node in BST :" << item <<endl; insert(item,p,parent); } void TNode::insert(int item,node * p,node * parent){ p->data=item; p->left=NULL; p->right=NULL; parent=NULL; if(isEmpty()){ root = p; } else{ node *ptr; ptr = root; while(ptr != NULL){ parent = ptr; if(item > ptr->data){ ptr = ptr->right; } else{ ptr = ptr->left; } } if(item < parent->data){ parent->left = p; } else{ parent->right = p; } } } void TNode::minNode(node* p){ while (p->left != NULL){ p = p->left; } cout << "Minimum value : " << p->data <<endl; } void TNode::maxNode(node* p){ while (p->right != NULL){ p = p->right; } cout << "Maximum value : " << p->data <<endl; } int TNode::countNodes(node* p){ int node = 1; //Node itself should be counted if (p == NULL){ return 0; } else{ node += countNodes(p->left); node += countNodes(p->right); return node; } } int TNode::treeHeight(node* p){ if (p == NULL) { return 0; } else { int left_side = treeHeight(p->left); int right_side = treeHeight(p->right); if (left_side > right_side) { return(left_side + 1); } else { return(right_side + 1); } } } void TNode::displayBinTree(){ cout <<endl<<endl; minNode(root); maxNode(root); cout <<"Height of BST : "<<treeHeight(root); cout <<"\nTotal nodes : "<<countNodes(root); } int main(){ TNode b; int data[] = {7,2,9,1,5,14}; cout <<"Constructing Binary Search Tree by Inserting Nodes One by One "<<endl; cout <<"------------------------------------------------------------- "<<endl; int arrSize = sizeof(data)/sizeof(data[0]); for(int i = 0; i < arrSize; i++) { b.buildTree(data[i]); } }

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MCD403 GDB 1 Solution and Discussion

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