• Cyberian's Gold

    Fall 2019
    MTH632: Complex Analysis and Differential Geometry
    Assignment No. 1 (Lectures # 1 to 12) Total Marks: 10
    Due Date: Tuesday, November 26, 2019

    Please read the following instructions before attempting the solution of this assignment:

    To solve this assignment, you should have good command over 1 to 12 lectures. 
    Try to consolidate your concepts that you learn in the lectures with these questions.
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    Question No. 1: Marks: 10

    Suppose that f(z)=x^2-y^2-2y+i(2x-2xy), where z=x+iy. Use the expressions
    x=(z+z ̅)/2 and y=(z-z ̅)/2i
    to write f(z) in terms of z, and simplify the result.

  • Cyberian's Gold

    Q. 1 Solution:
    b9eeee01-6b7a-407d-8de5-ceacfd63a89a-image.png

    f(z)=x^2-y^2-2y+i(2x-2xy)
    
    f(z)=(z+z ̅ )^2/4+(z-z ̅ )^2/4+i(z-z ̅ )+i(z+z ̅ )-(z+z ̅ )(z-z ̅ )/2
    
    f(z)=z^2/2+z ̅^2/2+2iz-z^2/2+z ̅^2/2
    
    f(z)=z ̅^2+2iz - ANSWER
    
  • Cyberian's Gold

    Q. 1 Solution:
    b9eeee01-6b7a-407d-8de5-ceacfd63a89a-image.png

    f(z)=x^2-y^2-2y+i(2x-2xy)
    
    f(z)=(z+z ̅ )^2/4+(z-z ̅ )^2/4+i(z-z ̅ )+i(z+z ̅ )-(z+z ̅ )(z-z ̅ )/2
    
    f(z)=z^2/2+z ̅^2/2+2iz-z^2/2+z ̅^2/2
    
    f(z)=z ̅^2+2iz - ANSWER
    
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