Fall 2019

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Total marks: 10
Due Date: 25 November, 2019
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Question 1:

The equation has exactly one real solutions. What can be deduced about the value of t? Marks=5

Question 2: Given a matrix

Apply the following row operations Marks=5

Here a=t, b=8, c=16

Discriminant = 0

The equation = tx2 – 8x + 16 = 0

b2 – 4ac = 0

by putting the values

(-8) 2 -4 (t) (16) = 0

64 - 64t = 0

t=1

**Q.2 Solution:**