MTH603 Quiz 2 Solution and Discussion

[zaasmi]

Whatwillbethevalueof′a′inthegivendividedifferencetable? x2468y0.51.11.72…21stD.D0.30.30.252ndD.Da−0.01253rdD.D−0.0021

[zaasmi]

@zaasmi said in MTH603 Quiz 2 Solution and Discussion:

For the given data points (1,0.3),(3,1),and(5,1.2) the divide difference table will be given as

Forthegivendatapoints(1,0.3),(3,1),and(5,1.2)thedividedifferencetablewillbegivenas

[zaasmi]

For the given data points (1,0.3),(3,1),and(5,1.2) the divide difference table will be given as

[zaasmi]

@zaasmi said in MTH603 Quiz 2 Solution and Discussion:

Δ=----- ?

E−1/2
1-E
E-1
None

[zaasmi]

Δ=----- ?

[zaasmi]

In Lagrange’s interpolation, for the given five points we can represent the function f (x) by a polynomial of degree

3
4
5
6

[zareen]

In Simpson’s 1/3 rule, the global error is of ………………

O(h2)
O(h3)
O(h4)
None of the given choices

[zareen]

Integration is a ………………process.

Subtracting
Summing
Dividing
None of the given choices

[zareen]

Which of the following is the Richardson’s Extrapolation limit: F1(h/2) provided that F(h/2) = F(h) = 1 ?

0
1
3
4

[zareen]

In the process of Numerical Differentiation, we differentiate an interpolating polynomial in place of ------------.

actual function

extrapolating polynomial

Lagrange’s polynomial

Newton’s Divided Difference Interpolating polynomial

[zareen]

Richardson extrapolation is method also known as …………

Sequence acceleration method
Series acceleration method

Ref
In numerical analysis, Richardson extrapolation is a sequence acceleration method, used to improve the rate of convergence of a sequence. It is named after Lewis Fry Richardson, who introduced the technique in the early 20th century.

[zareen]

We prefer ………over the Lagrange’s interpolating method for economy of computation.

Newton’s forward difference method

Newton’s backward difference method

Newton’s divided difference method

none.

[zareen]

Which of the following is the Richardson’s Extrapolation limit: F3(h/8)
provided that F2(h/8) = F2(h/4) = 1 ?

63
64
1
-1

[zareen]

1st ordered divided difference formula is defined as…
y[x0,x1]=(y1-y0)/(x1-x0)
y[x0,x1]=(y1+y0)/(x1-x0)
y[x0,x1]=(y1-y0)/(x1+x0)