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ENG510 Assignment 2 Solution and Discussion

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MAELT
Sociolinguistics (Eng510)

Fall 2019
Assignment No. 2
Total Marks: 20
Lectures: 21-30

Instructions:

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Q1. In this technological age of computers and social media, standard spellings and grammar are getting extinct. Shorthand English also called chat language is becoming a social norm. Most of the students use it in their academic writings and formal email communications even. You are supposed to pick and write 10 examples of chat language from the Facebook interface. (10 Marks)

Q2. Brown and Levinson outline four main types of politeness strategies: bald on-record, negative politeness, positive politeness, and off-record (indirect). Differentiate between negative politeness and positive politeness giving their exact definitions. Read the given statements carefully and label them with correct type of politeness strategy.
(5+5+10 Marks)

Sr. No.	Statements	Politeness strategy
1	Don’t forget to clean the blinds!
2	Could you please pass the rice?
3	Wow, it’s getting cold here.
4	You look sad. Can I do anything?
5	Leave it; I’ll clean it up later.

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Q. 1 Solution:
Starting from lower side of circuit network, we can see that 2Ω and 2Ω are in series, so their combined effect is
2+2=4Ω

This 4Ω is in parallel of 4Ω to lower side, so their equivalent is

This 2Ω is in series of 5Ω and 1Ω, so the sum of series resistances is

2Ω+ 5Ω+1Ω=8Ω

Now at upper side, 4Ω and 2Ω are in series
4Ω+ 2Ω=6Ω

This 6Ω is in parallel of 6Ω, so their equivalent is

This 3Ω is in series of 3Ω and 1Ω, so the sum of series is

3Ω+ 3Ω+1Ω=7Ω

Now we can see 7Ω becomes in series of 8Ω, so equivalent resistance is
Req =7Ω + 8Ω
Req=15Ω

Q.2 Solution:
1)
To calculate the source current Is, Firstly, we calculate the total resistance
RT= R1+R2+R3
=6Ω
V=IR
IS=VS/RT
= 12/6
=2A

2)
Since all resistances are in series, same 2A current pass through each resistance.
V1= R1IS
=12
=2V
V2=R2Is
=22
=4V
V3=R3IS
= 32
=6V

3)
P1 =I2R1
= (2)2 *1
=4W
P2 =I2R2
= (2)2 *2
= 8W
P3 =I2R3
=(2)2 *3
= 12W
= 12W

4)-
Ps = VsIs
P =122
=24 W
PT=P1+P2+P3 or PT=I2RT
=4+8+12
=24 W
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Idea Solution:
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Four types of market structure
Monopolistic competition
Oligopoly
Monopoly
Perfect competition
In our case there is a perfect competition because so many sellers having identical or same products. Which are characteristics of perfect competition.

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Pure or perfect competition is a theoretical market structure in which the following criteria are met: all firms sell an identical product (the product is a “commodity” or “homogeneous”); all firms are price takers (they cannot influence the market price of their product); market share has no influence on price; buyers have complete or “perfect” information – in the past, present and future – about the product being sold and the prices charged by each firm; resources such a labor are perfectly mobile; and firms can enter or exit the market without cost.

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Solution:
Question no. 1:
Test the hypothesis that the mean of a normal population with known variance 70 is 31, if a sample of size 13 gave x ̅ = 34. Let the alternative hypothesis be H1: µ > 31, and let α = 0.10.
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Formulation of Hypothesis:
Ho: µ = 31
H1: µ > 31
Level of Significance:
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Calculation:
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Reject Ho, if
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Questions no. 2:
Explain in detail why it is not a good statistical procedure to perform several t-test on pairs of means , when several means are to be compared. Suggest the alternative statistical procedure and also give its assumptions.
Solution:
Whenever we compare more than two population means, we apply the two-sample t-test to all possible pairwise comparisons of means. For example, if we wish to compare 4 population means, there will be 6 pairs and to test the hypothesis that all four population means are equal, would require six two-sample t-test. This type of multiple two-sample t-test has two disadvantages. First, the procedure is difficult and time consuming and secondly, the level of significance increases as the number of t-test increases. Thus, a series of two-sample t-test is not a good procedure. ANOVA is a technique that measure the variations between the means.
Assumptions of ANOVA:
1: Experimental errors are normally distributed.
2: Equal variance between the treatments.
3: Samples are independent.

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