It would be perpendicular to the graph of \(y=\dfrac{1}{6}x+3\).

It would be parallel to the graph of \(12y=2x+3\).

It would have the same slope as the graph of \(x+6y=18\).

It would have the same \(y\)‑intercept as the graph of \(y=\dfrac{1}{6}x+12\).

I would be guessing.

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